bigedd wrote:6000 feet x 20ftwide x 6 inches thick of gravel. How many tons of gravel do I need.
6000' * 20' * 0.5' = 60000 ft^3
60000 ft^3 / 27 yd^3 = 2222.22 yd^3
2222.22 yd^3 * 3400 lbs/yd^3 = 7,555,556 lbs
7,555,556 lbs / 2000 = 3777.78 tons
Open question so answer is approximate. More information is needed.
Assuming loose wet gravel from S&G pit using standard weights of materials chart. Actual weight of gravel needs to be determined at S&G scales. No compaction is calculated.
If this is a road, use crushed base instead.
