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How convert syngas Nm3/h to kg/h

Thu May 07, 2009 2:43 pm

How convert syngas 184867 Nm3/h to kg/h ?

Re: How convert syngas Nm3/h to kg/h

Fri May 08, 2009 5:25 am

Destroy wrote:How convert syngas 184867 Nm3/h to kg/h ?


Syngas is a mix of CO and H2, with possibly a few impurities. However, the ratio of CO to H2 depends on what was steam reformed. Unless you know the proportions by gas analysis (or at least stoichiometry from what was reformed) you can not calculate average molecular weight or density.

Fri May 08, 2009 4:55 pm

H2 = 73 %, CO = 6,2 %, CO2 = 2 %, N2 = 18 %

Sat May 09, 2009 12:42 am

Destroy wrote:H2 = 73 %, CO = 6,2 %, CO2 = 2 %, N2 = 18 %


Average molecular weight

0.73*2 + 0.062*28 + 0.02*44 + 0.18*28 = 9.116 Da, so the molar mass is 9.116 g/mol.

At "normal" conditions, 101.325 kPa, 0 °C, a mole of ideal gas occupies 22.414 L.

184867 Nm³/h x 1 kmol/22.414 m³ x 9.116 kg/kmol = 75187 kg/h

Mon May 11, 2009 3:41 pm

Great thanks!!!

Re: OBS

Fri Apr 23, 2010 6:51 pm

Destroy wrote:Great thanks!!!


Be careful here: Nm3 has nothing to do with m3 and L, since the unit is a molar amount and not a volume. Istead: find out how many kmol equals 1Nm3.

Re: Oops

Fri Apr 23, 2010 7:09 pm

Vinni wrote:
Destroy wrote:Great thanks!!!


Be careful here: Nm3 has nothing to do with m3 and L, since the unit is a molar amount and not a volume. Istead: find out how many kmol equals 1Nm3.


Ah.. I didn't see the phrase "Normal conditions" :) Yes, when the ideal gas law applies, then it's correct: nRT=Vp

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