Questions and answers on how to convert things from one unit or system to another
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Fri Nov 04, 2005 9:56 pm
Hello,
Could some one please help me with a conversion from mg/litre to tons? I have an storm water application that the state of Maryland requires a water sampling that is in concentration as well as mass. I have the mg/litre data, not the tons.
Thanks,
marauder96
Sat Nov 05, 2005 12:33 am
You need to explain the problem better for us to help.
The mg/L data is a concentration of some contaminant per liter of water. 1 L of distilled water at 4 degrees C weighs 1 kg, and this figure is close enough for for reasonably clean rain water at 10 or 20 degrees C too (it does very slightly with temperature.
I assume you are concerned with total amounts of water in tons. 1000 L = 1 m^3, and 1 m^3 of water under the above conditions weighs 1000 kg or 1 metric ton (the term tonne is used in many other countries). The concentration would have the same numerical value in units of g/t (grams per metric ton), and you could multiply by metric tons of water to determine total amount of contaminant.
You may need to work in US (short) tons of 2000 lbs rather than metric tons (1000 kg = 2204.622 6 lbs)
Sun Nov 13, 2005 8:35 am
Anonymous wrote:You need to explain the problem better for us to help.
The mg/L data is a concentration of some contaminant per liter of water. 1 L of distilled water at 4 degrees C weighs 1 kg, and this figure is close enough for for reasonably clean rain water at 10 or 20 degrees C too (it does very slightly with temperature.
I assume you are concerned with total amounts of water in tons. 1000 L = 1 m^3, and 1 m^3 of water under the above conditions weighs 1000 kg or 1 metric ton (the term tonne is used in many other countries). The concentration would have the same numerical value in units of g/t (grams per metric ton), and you could multiply by metric tons of water to determine total amount of contaminant.
You may need to work in US (short) tons of 2000 lbs rather than metric tons (1000 kg = 2204.622 6 lbs)
:oops: :oops: :oops: :wink:
Wed Dec 07, 2005 11:30 pm
Try this formula, it work for me.
=(mg/l*Gallons)*(1/2000)*(1/0.26)*(2.204)*(1/1000000)
Good Luck
Jay ;-)
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