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Tue May 10, 2005 9:55 pm
Could you please help me figure out how to calculate the quantity in volume (Liter) of oxygen (gas) from 200 grams of hydrogen peroxide (H2O2) and 55 grams of peracetic acid (CH3COOOH)?
2H2O2(aq) -------> 2H2O + O2 (g)
2CH3COOOH(aq) -------> 2CH3COOH + O2 (g)
(Temperature =20 C, Pressure = 1 atp)
Thank you very much.
Poopaechalisa
(From Thailand)
Wed May 11, 2005 12:00 am
Steps:
1) Determine the molegular weights of the relevant reactants
(rounded values H2O2 is 34, O2 is 32), and compute the number of moles of H2O2 available
2) Note from the equation that 2 moles of H2O2 produces 1 mole of O2 and determine moles of O2.
3) Use the Ideal Gas Equation, PV = nRT, to determine the volume, at the specified conditions, of that many moles of O2.
4) Follow the same general approach for the 2nd problem.
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