JB wrote:If i needed to store 5.2 acre foot of water how long, wide, deep of a basin would i need.
You basically have to pick two dimensions and divide into total volume to get the third.
5.2 acres x 1 foot deep, or 0.52 acres by 10 foot deep, etc.
An acre is 43560 ft², so 5.2 acre-foot is 266512 ft³. How about a nice 66' x 66' x 52' rectangular solid? (Or any other three numbers with the same product, like 132' x 132' x 13')
